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Chapters 8 & 9 Practice Assignment

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Missing Value
Numeric Outliers
H0: μ = 6200Ha: μ ≠ 6200Reject the null hypothesis because the p-value is less than 0.05.
Single sample t-test
Rule Engine
H0: p = 0.12Ha: p > 0.12Sample proportion = 0.171One-tail p-value = 0.0000 ÷ 2 = 0.0000Reject the null hypothesis because the p-value is less than 0.05.
Single sample t-test
H0: Attrition and Department are independent.Ha: Attrition and Department are dependent.Chi-square statistic = 9.844Degrees of freedom (df) = 2p-value = 0.007Reject the null hypothesis because the p-value is less than 0.05.
Crosstab

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